Thursday, February 17, 2011

Workdone in a Steady Flow Process

The steady flow equation for unit mass flow, in the differential form, is

                           &q - &w = dh + d(ke) + d(pe)

According to first law of thermodynamics for a closed system, we know that
&q = du +pdv
or
dh = &q +v dp
substituting this value of dh in equation
&q - &w = (&q + v dp) + d(ke) + d(pe)
- &w = v dp + d(ke) + d(pe)

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